[petsc-users] Using KSPLSQR without explicitly computing U(transpose)U
Jed Brown
jed at 59A2.org
Sun Jan 23 08:40:57 CST 2011
On Sun, Jan 23, 2011 at 03:39, Gaurish Telang <gaurish108 at gmail.com> wrote:
> But for this I had to compute U(transpose)U explicitly. The algorithm
> mentioned in the paper does NOT involve an explicit computation of
> U(transpose)U.
>
> Is there a way to avoid the explicit and expensive computation of
> U(transpose)U and use KSPLSQR? The details on this page
>
The need for explicit U^T U is for algebraic preconditioners (like
incomplete factorization). You can try using cheaper approximations to this
product or use a PCShell if you want to avoid explicitly forming the
product. Chances are that unpreconditioned LSQR will converge too slowly.
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