[Swift-devel] Join function?

[Glen Hocky]

p.s. With regards to my previous email. I seemed to be getting this error,
which looks like it was/should have been address a long time ago
http://lists.ci.uchicago.edu/pipermail/swift-devel/2009-June/005724.html

On Tue, Apr 3, 2012 at 3:09 PM, Glen Hocky <glen842 at uchicago.edu> wrote:

> This seemed like an interesting challenge. The following works assuming
> swift knows how many elements you have. However, there are many simpler
> things I would /think/ should work that do not. There seem to possibly be
> some bugs (i.e. things that don't seem intentional) about declaring a
> variable before an iterate statement and then writing to it on each iterate
> statement. Hence the use of lists below. I will also put a second version
> after which I would think should work but does not
>
> Working:
>
> $ swift test.swift
>> Swift svn swift-r3826 cog-r2988
>> RunID: 20120403-1509-3xnsrx10
>> Progress:
>> SwiftScript trace: this:is:a:test
>> Final status:
>
>
>
> (string j[]) join(string s[], string c, int n){
>>     j[0]="";
>>     iterate i {
>>         if(i<n-1){
>>             j[i+1]=@strcat( j[i], s[i]+c );
>>         }
>>         else{
>>             j[i+1]=@strcat( j[i], s[i] );
>>         }
>>     } until(i==n-1);
>>
>> }
>> string a[];
>> a[0] = "this";
>> a[1] = "is";
>> a[2] = "a";
>> a[3] = "test";
>> int nelements=4;
>> string j[];
>> j = join( a, ":", nelements );
>> trace(j[nelements]);
>
>
> Not working (error, jlist has multiple writers):
>
>> (string j) join(string s[], string c, int n){
>>     string jlist[];
>>     jlist[0] = "";
>>     iterate i {
>>         if(i<n-1){
>>             jlist[i+1]=@strcat( jlist[i], s[i]+c );
>>         }
>>         else{
>>             jlist[i+1]=@strcat( jlist[i], s[i] );
>>         }
>>     } until(i==n-1);
>>     j = jlist[n];
>>
>> }
>> string a[];
>> a[0] = "this";
>> a[1] = "is";
>> a[2] = "a";
>> a[3] = "test";
>> int nelements=4;
>> string j;
>> j = join( a, ":", nelements );
>> trace(j);
>
>
>
>
> On Tue, Apr 3, 2012 at 2:02 PM, David Kelly <davidk at ci.uchicago.edu>wrote:
>
>> Hello,
>>
>> Is there a way to concatenate all elements of an array into a single
>> string? I would also like to define a separator between elements. I was
>> thinking of something similar to Perl's join function.
>>
>> If I have:
>>
>> string a[];
>> a[0] = "this";
>> a[1] = "is";
>> a[2] = "a";
>> a[3] = "test";
>>
>> How can I get it into "this is a test" or "this:is:a:test"? @strcat
>> returns a reference. I can tracef with %q and get "[this,is,a,test]", but
>> it doesn't give me any control over the formatting as far as I know.
>>
>> I could call a shell script to do this, just wondering if there was
>> another way.
>>
>> David
>> _______________________________________________
>> Swift-devel mailing list
>> Swift-devel at ci.uchicago.edu
>> https://lists.ci.uchicago.edu/cgi-bin/mailman/listinfo/swift-devel
>>
>
>
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.mcs.anl.gov/pipermail/swift-devel/attachments/20120403/f5ed4305/attachment.html>