[petsc-users] Strange behavior of TS after setting hand-coded Jacobian
仓宇
yhcy1993 at gmail.com
Sun Nov 7 02:45:45 CST 2021
Thanks for your patient explanation, and sorry for this late reply.
I do understand the manipulation skills that you mentioned, but this kind
of manually substitution will not change the numerical difficulty of the
problem.
In fact, before I turn to PETSc, I have tried to form an ODE for this
problem already, by utilizing the well-established functions like 'ode15s'
and 'ode23' in MATLAB. But it failed to produce physically reasonable
results. The key flaw lies in the treatment of the eigenvalue, namely
\hat{\Lambda}_r denoted in the PDF file. Only implicit DAE formulation can
fully embody its effect. This is why I finally decided to turn to use the
DAE functionality in PETSc.
I've excerpted some description from a monograph regarding this problem,
hope it can clearly demonstrate the numerical requirement for solving it.
[image: bvp.png]
Kee, R. J., Coltrin, M. E., Glarborg, P., & Zhu, H. (2017). Stagnation
Flows. In *Chemically Reacting Flow* (2 ed., pp. 232).
Zhang, Hong <hongzhang at anl.gov> 于2021年11月1日周一 下午10:21写道：
> You can avoid the zero-diagonal elements in your case. Just remove the
> boundary points and the \hat{\Lambda}_r from the solution vector Y (eq(17)
> in your PDE file). You can calculate them separately in your RHS function
> (when computing the residual vector for 2 <=i<=N-1). It is not necessary to
> form a DAE. You can actually form an ODE instead.
>
> Hong (Mr.)
>
> > On Oct 31, 2021, at 5:38 AM, 仓宇 <yhcy1993 at gmail.com> wrote:
> >
> > Thanks for your suggestions and experience sharing.
> >
> > But it seems that you have missed my point. This kind of zero-diagonal
> > element that I described earlier is somehow inevitable.
> > If interested in this problem, you may refer to the PDF file that was
> > attached in the previous post.
> >
> > Regards
> >
> > Yu
> >
> > Zhang, Hong <hongzhang at anl.gov> 于2021年10月29日周五 下午10:05写道：
> >>
> >> One way to avoid the zero element in Jacobian is to exclude the
> boundary point from the solution vector. I often do this for Dirichlet
> boundary conditions since the value at the boundary is given directly and
> does not need to be taken as a degree of freedom.
> >>
> >> Hong (Mr.)
> >>
> >> On Oct 28, 2021, at 9:49 PM, 仓宇 <yhcy1993 at gmail.com> wrote:
> >>
> >> Thanks for your careful inspection and thoughtful suggestions.
> >>
> >>> finite differencing may put a small non-zero value in that location
> due to numerical round-off
> >>
> >> I think your explanation is reasonable. This numerical round-off may
> somehow help to avoid this pivot issue.
> >>
> >> The structure of my jacobian matrix looks like this (generated by
> '-mat_view draw'):
> >> <jac_view.png>
> >> Analytically, the first diagonal element of the jacobian is indeed 0,
> as its corresponding residual function is solely determined from boundary
> condition of another variable. This seems a little bit wired but is
> mathematically well-posed. For more description about the background
> physics, please refer to attached PDF file for more detailed explanation on
> the discretization and boundary conditions.
> >>
> >> Actually, the jacobian matrix is not singular, but I do believe this
> numerical difficulty is caused by the zero-element in diagonal.
> >> In this regard, I've performed some trial and test. It seems that
> several methods have been worked out for this pivot issue:
> >> a) By setting '-pc_type svd', PETSC does not panic any more with my
> hand-coded jacobian, and converged solution is obtained. Efficiency is also
> preserved.
> >> b) By setting '-pc_type none', converged solution is also obtained, but
> it takes too many KSP iterations to converge per SNES step (usually
> hundreds), making the overall solution procedure very slow.
> >>
> >> Do you think these methods really solved this kind of pivot issue? Not
> by chance like the numerical round-off in finite difference previously.
> >>
> >> Regards
> >>
> >> Yu Cang
> >>
> >> Barry Smith <bsmith at petsc.dev> 于2021年10月27日周三 下午9:43写道：
> >>>
> >>>
> >>> You can run with -ksp_error_if_not_converged to get it to stop as
> soon as a linear solve fails to help track down the exact breaking point.
> >>>
> >>>> The problem under consideration contains an eigen-value to be solved,
> >>>> making the first diagonal element of the jacobian matrix being zero.
> >>>> From these outputs, it seems that the PC failed to factorize, which is
> >>>> caused by this 0 diagonal element. But I'm wondering why it works
> >>>> with jacobian matrix generated by finite-difference?
> >>>
> >>> Presumably your "exact" Jacobian puts a zero on the diagonal while
> the finite differencing may put a small non-zero value in that location due
> to numerical round-off. In that case even if the factorization succeeds it
> may produce an inaccurate solution if the value on the diagonal is very
> small.
> >>>
> >>> If your matrix is singular or cannot be factored with LU then you
> need to use a different solver for the linear system that will be robust to
> the zero on the diagonal. What is the structure of your Jacobian? (The
> analytic form).
> >>>
> >>> Barry
> >>>
> >>>
> >>>> On Oct 27, 2021, at 1:47 AM, 仓宇 <yhcy1993 at gmail.com> wrote:
> >>>>
> >>>> Thanks for your kind reply.
> >>>>
> >>>> Several comparison tests have been performed. Attached are execution
> >>>> output files. Below are corresponding descriptions.
> >>>>
> >>>> good.txt -- Run without hand-coded jacobian, solution converged, with
> >>>> option '-ts_monitor -snes_monitor -snes_converged_reason
> >>>> -ksp_monitor_true_residual -ksp_converged_reason';
> >>>> jac1.txt -- Run with hand-coded jacobian, does not converge, with
> >>>> option '-ts_monitor -snes_monitor -snes_converged_reason
> >>>> -ksp_monitor_true_residual -ksp_converged_reason -snes_test_jacobian';
> >>>> jac2.txt -- Run with hand-coded jacobian, does not converge, with
> >>>> option '-ts_monitor -snes_monitor -snes_converged_reason
> >>>> -ksp_monitor_true_residual -ksp_converged_reason -snes_test_jacobian
> >>>> -ksp_view';
> >>>> jac3.txt -- Run with hand-coded jacobian, does not converge, with
> >>>> option '-ts_monitor -snes_monitor -snes_converged_reason
> >>>> -ksp_monitor_true_residual -ksp_converged_reason -snes_test_jacobian
> >>>> -ksp_view -ts_max_snes_failures -1 ';
> >>>>
> >>>> The problem under consideration contains an eigen-value to be solved,
> >>>> making the first diagonal element of the jacobian matrix being zero.
> >>>> From these outputs, it seems that the PC failed to factorize, which is
> >>>> caused by this 0 diagonal element. But I'm wondering why it works
> >>>> with jacobian matrix generated by finite-difference? Would employing
> >>>> DMDA for discretization be helpful?
> >>>>
> >>>> Regards
> >>>>
> >>>> Yu Cang
> >>>>
> >>>> Barry Smith <bsmith at petsc.dev> 于2021年10月25日周一 下午10:50写道：
> >>>>>
> >>>>>
> >>>>> It is definitely unexpected that -snes_test_jacobian verifies the
> Jacobian as matching but the solve process is completely different.
> >>>>>
> >>>>> Please run with -snes_monitor -snes_converged_reason
> -ksp_monitor_true_residual -ksp_converged_reason -snes_test_jacobian and
> send all the output
> >>>>>
> >>>>> Barry
> >>>>>
> >>>>>
> >>>>>> On Oct 25, 2021, at 9:53 AM, 仓宇 <yhcy1993 at gmail.com> wrote:
> >>>>>>
> >>>>>> I'm using TS to solve a set of DAE, which originates from a
> >>>>>> one-dimensional problem. The grid points are uniformly distributed.
> >>>>>> For simplicity, the DMDA is not employed for discretization.
> >>>>>>
> >>>>>> At first, only the residual function is prescribed through
> >>>>>> 'TSSetIFunction', and PETSC produces converged results. However,
> after
> >>>>>> providing hand-coded Jacobian through 'TSSetIJacobian', the internal
> >>>>>> SNES object fails (residual norm does not change), and TS reports
> >>>>>> 'DIVERGED_STEP_REJECTED'.
> >>>>>>
> >>>>>> I have tried to add the option '-snes_test_jacobian' to see if the
> >>>>>> hand-coded jacobian is somewhere wrong, but it shows '||J -
> >>>>>> Jfd||_F/||J||_F = 1.07488e-10, ||J - Jfd||_F = 2.14458e-07',
> >>>>>> indicating that the hand-coded jacobian is correct.
> >>>>>>
> >>>>>> Then, I added a monitor for the internal SNES object through
> >>>>>> 'SNESMonitorSet', in which the solution vector will be displayed at
> >>>>>> each iteration. It is interesting to find that, if the jacobian is
> not
> >>>>>> provided, meaning finite-difference is utilized for jacobian
> >>>>>> evaluation internally, the solution vector converges to steady
> >>>>>> solution and the SNES residual norm is reduced continuously.
> However,
> >>>>>> it turns out that, as long as the jacobian is provided, the solution
> >>>>>> vector will NEVER get changed! So the solution procedure stucked!
> >>>>>>
> >>>>>> This is quite strange! Hope to get some advice.
> >>>>>> PETSC version=3.14.6, program run in serial mode.
> >>>>>>
> >>>>>> Regards
> >>>>>>
> >>>>>> Yu Cang
> >>>>>
> >>>> <jac3.txt><jac2.txt><jac1.txt><good.txt>
> >>>
> >> <TFM.pdf>
> >>
> >>
>
>
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