[petsc-users] fieldsplit: Unhandled case, must have at least two fields, not 1!
Nico Schlömer
nico.schloemer at gmail.com
Thu Nov 28 10:28:18 CST 2013
Hi Jed,
thanks for the quick answer!
I can of course generate the strided index sets (01x34x6...,
xx2xx5x...) myself and insert them via PCFieldSplitSetIS(), but I
thought that ultimately does the same thing that I would have liked
PCFieldSplitSetFields() to do for me. Not true?
--Nico
On Thu, Nov 28, 2013 at 4:25 PM, Jed Brown <jedbrown at mcs.anl.gov> wrote:
> Nico Schlömer <nico.schloemer at gmail.com> writes:
>
>> Hi all,
>>
>> I'm toying around with PETSc's field split capabilities for the
>> 2D-Stokes problem, and similar to ex42 I call
>>
>> // set of the operators
>> // set of a bunch of options
>> PetscOptionsSetValue("-pc_type", "fieldsplit");
>> PC pc;
>> ierr = KSPGetPC(*_ksp, &pc);
>> const PetscInt ufields[] = {0,1}, pfields[] = {2};
>> ierr = PCFieldSplitSetBlockSize(pc,3);
>> PCFieldSplitSetFields(pc,"u",2,ufields,ufields);
>> PCFieldSplitSetFields(pc,"p",1,pfields,pfields);
>>
>> When finally solving, however, I'm getting the error message
>>
>> [0]PETSC ERROR: Petsc has generated inconsistent data!
>> [0]PETSC ERROR: Unhandled case, must have at least two fields, not 1!
>
> Short answer: use PCFieldSplitSetIS(). From the man page:
>
> Notes: Use PCFieldSplitSetIS() to set a completely general set of indices as a field.
>
> The PCFieldSplitSetFields() is for defining fields as strided blocks. For example, if the block
> size is three then one can define a field as 0, or 1 or 2 or 0,1 or 0,2 or 1,2 which mean
> 0xx3xx6xx9xx12 ... x1xx4xx7xx ... xx2xx5xx8xx.. 01x34x67x... 0x1x3x5x7.. x12x45x78x....
> where the numbered entries indicate what is in the field.
>
> This function is called once per split (it creates a new split each time). Solve options
> for this split will be available under the prefix -fieldsplit_SPLITNAME_.
>
> Developer Note: This routine does not actually create the IS representing the split, that is delayed
> until PCSetUp_FieldSplit(), because information about the vector/matrix layouts may not be
> available when this routine is called.
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