[petsc-users] RE : RE : How to get bandwidth peak out of PETSc log ?
HOUSSEN Franck
Franck.Houssen at cea.fr
Fri Jun 21 07:10:05 CDT 2013
It seems performance are always the same whatever the number of threads.
I ran all these tests on my laptop (which is not a "great supercomputer" !... As Matt noticed, and as I knew it !)
FH
~/Bandwidth>export OMP_NUM_THREADS=1
~/Bandwidth>./stream_c.exe > stream_1thread.log
~/Bandwidth>export OMP_NUM_THREADS=2
~/Bandwidth>./stream_c.exe > stream_2threads.log
~/Bandwidth>export OMP_NUM_THREADS=4
~/Bandwidth>./stream_c.exe > stream_4threads.log
~/Bandwidth>grep Triad *log
stream_1thread.log:Triad: 13057.6 0.018427 0.018380 0.018539
stream_2threads.log:Triad: 13044.9 0.018496 0.018398 0.018936
stream_4threads.log:Triad: 13049.1 0.018449 0.018392 0.018561
________________________________________
De : Jed Brown [five9a2 at gmail.com] de la part de Jed Brown [jedbrown at mcs.anl.gov]
Date d'envoi : vendredi 21 juin 2013 12:41
À : HOUSSEN Franck; Barry Smith
Cc: petsc-users at mcs.anl.gov
Objet : Re: [petsc-users] RE : How to get bandwidth peak out of PETSc log ?
HOUSSEN Franck <Franck.Houssen at cea.fr> writes:
> MatMult 13216 1.0 5.4614e+01 1.0 5.52e+10 1.0 0.0e+00 0.0e+00 0.0e+00 21 56 0 0 0 21 56 0 0 0 1010
Much of your time is spent here, which is bandwidth limited. It needs 6
bytes per flop (plus a little, if the vector is perfectly reused) , so
this number is about 6 GB/s.
> MatMult 13550 1.0 3.8204e+01 1.0 2.85e+10 1.0 2.7e+04 3.5e+04 0.0e+00 23 55 79 93 0 23 55 79 93 0 1494
Here with two processes, you have about 9 GB/s.
Was your STREAM test (getting 11 GB/s) using multiple threads/processes?
Can you send STREAM results for one and for two threads? 50% of STREAM
is not very good (though it's actually the best you can do on some funny
architectures), 70-85% is what we expect.
If you're getting a low fraction of peak in MatMult, try reordering your
matrix to have lower bandwidth. You can use MatGetOrdering with RCM for
this.
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