[petsc-users] Options to set when solving Ax=b if matrix A changes its non-zero position at each solve
TAY wee-beng
zonexo at gmail.com
Sun Jun 10 04:42:12 CDT 2012
Hi,
Currently, my matrix A changes its non zero position at each time step.
For e.g.: At a particular node, at time step = 1, I will insert values
into its east, west neighbours. At time step = 2, I will insert values
into its east, north neighbours. Hence, the non-zero positions at each
row will be different at each time step. However, the max values per row
will always be 5 or less.
Currently, after MatSetValues and MatAssemblyBegin/End, I call:
/call MatSetOption(A_mat,MAT_NEW_NONZERO_LOCATIONS,PETSC_TRUE,ierr)
call KSPSetOperators(ksp,A_mat,A_mat,DIFFERENT_NONZERO_PATTERN,ierr)
call KSPGetPC(ksp,pc,ierr)
ksptype=KSPBCGS
call KSPSetType(ksp,ksptype,ierr)
call KSPSetFromOptions(ksp,ierr)
call KSPSolve(ksp,b_rhs,xx,ierr)/
Is this sufficient and correct? If so, apart from KSPSolve, MatSetValues
and MatAssemblyBegin/End, can I only call the other subroutines once at
the 1st time step?
Or do I have to explicitly destroy the matrix and create a new one? I
think I ask this question a while ago but I can't find the email now.
--
Yours sincerely,
TAY wee-beng
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