[Nek5000-users] Reading binary data

[nek5000-users at lists.mcs.anl.gov]

No, if a field file only contains the geometry (mesh coordinates) nfields is equal to ndim (2 or 3).
Stefan


On Aug 12, 2010, at 12:01 AM, <nek5000-users at lists.mcs.anl.gov> wrote:

> Stefan,
> 
> Thanks.  I figured that, but the binary file size doesn't seem to be adding up.    For example,  a field file that doesn't have geometry data is the size described by the initial thread, i.e.
> 
> 132 bytes + 4 bytes + nel* 4 bytes + nfields*nxyz*nel* wdsizo  +  nfields*2*nel * 4 bytes
> 
> My naive assumption was that a field file with xyz data would then have the additional space requirement of
> 
> nx*ny*nz*nel*wdsizo
> 
> but the file's bigger than that.  What info am I missing?  
> 
> --Mike
> 
> On Aug 11, 2010, at 3:50 PM, <nek5000-users at lists.mcs.anl.gov> wrote:
> 
>> Hi Mike,
>> 
>> vector fields (e.g. mesh coordinates) are stored in the following way:
>> 
>> LOOP over all elements
>> 	LOOP i = {x,y,z}
>> 		 i for all GLL points (internal element points)
>> 	ENDLOOP
>> ENDLOOP
>> 
>> 2D example with (E=2,N=2):
>> x1_1 x2_1 x3_1 y1_1 y2_1 y3_1 x1_1 x2_2 x3_2 y1_2 y2_2 y3_2
>> 
>> where x2_1 means the x-coordinate of the 2nd GLL point of element 1.
>> 
>> hth,
>> Stefan 
>> 
>> On Aug 11, 2010, at 11:34 PM, <nek5000-users at lists.mcs.anl.gov> wrote:
>> 
>>> 
>>> Hello All.  I found this helpful message from Stefan regarding the structure of a binary field file.   Could someone please tell me what the structure is when the geometry info is also contained?
>>> 
>>> Thanks!
>>> --Mike
>>> 
>>> nek5000-users at lists.mcs.anl.gov nek5000-users at lists.mcs.anl.gov 
>>>> Thu May 6 07:18:03 CDT 2010
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>>>> Hi Fred,
>>>> 
>>>> header: 132 bytes
>>>> endian test tag: 4 bytes
>>>> element mapping: nel* 4 bytes
>>>> data: nfields*nxyz*nel* wdsizo (where wdsizo is 4 or 8 bytes)
>>>> metadata (min/max values): nfields*2*nel * 4 bytes
>>>> 
>>>> Stefan
>>>> 
>>> 
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