[mpich-discuss] mpdboot

[Dave Goodell]

If there is only a single machine, you can just run "mpd &" on that  
machine.  There is no need to use mpdboot.  However if you ever get an  
additional machine, you should invoke mpdboot as:

-------8<-------
mpdboot --ncpus=<N_ON_CURRENT_HOST> -n <NUM_MPDS_TO_START> -f <HOSTFILE>
-------8<-------

Where <HOSTFILE> contains something like:

-------8<-------
hostA:8
hostB:8
hostC:8
-------8<-------

Where hostA/hostB/hostC is the hostname of each host you want to  
participate in the ring and "8" is the number of cores for that host.

You can also use hydra, which has a slightly less complicated user  
interface and doesn't require setting up daemons before running the  
job: http://wiki.mcs.anl.gov/mpich2/index.php/Using_the_Hydra_Process_Manager

-Dave

On Feb 10, 2010, at 8:06 AM, madhurjyap.bora at gmail.com wrote:

> What should be contents of $HOME/machines. Note that it is a single  
> machine
> with dual CPU each having four cores.
>
> --- Madhurjya
>
> > mpdboot -n 8 -f $HOME/machines
> >
> > try above command
> >
> > On Wed, Feb 10, 2010 at 12:41 AM, Madhurjya P Bora <
> > madhurjyap.bora at gmail.com> wrote:
> >
> >> Dear List,
> >>
> >> I have a Linux machine with two quad-core Intel (Xeon) CPUs  
> (total 8 cores)
> >> and installed MPICH2 successfully with Intel IFORT and ICC  
> compilers.
> >> But it seems that it is not fully using the all cores.
> >>
> >> Does it have any relation to invking mpdboot? What is the proper  
> way to
> >> invoke mpdboot? Right now I use,
> >>
> >> $ mpdboot
> >>
> >> But it gives different timing when mpdboot is invoked with -- 
> ncpus=2, 4,
> >> and 8.
> >>
> >> Any help is appreciated.
> >>
> >>
> >> -- Madhurjya_______________________________________________
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