[Nek5000-users] Reading binary data

[nek5000-users at lists.mcs.anl.gov]

The 12288 bytes is the metadata for all 3 mesh coordinates:
ndim * nel * 2 * 4 bytes 

Stefan

On Aug 12, 2010, at 12:21 AM, <nek5000-users at lists.mcs.anl.gov> wrote:

> Sorry -- I'm still not getting it.
> 
> The first file had mesh coordinates and field information in it; here is what the header shows:
> 
> #std 4  8  8  8        512        512  0.2000000000000E+02      1000      0      1 XUPS02 
> 
> The size of this file is  9476232, but I can't figure out what is contributing to that size.  For the next field file, the header shows:
> 
> #std 4  8  8  8        512        512  0.1200000000000E+03      6000      0      1 UPS02 
> 
> The size of this file is 6318216, which is exactly predicted by the expression below -- all is well.
> 
> What is the makeup of the 3158016 bytes difference between these files?  The mesh coordinates alone are only
> 
> 512 * 8^3 * 4 * 3 (ndim) = 3145728 bytes
> 
> Where and what are the remaining 12288 bytes?
> 
> Thanks.
> 
> 
> 
> On Aug 11, 2010, at 4:09 PM, <nek5000-users at lists.mcs.anl.gov> wrote:
> 
>> No, if a field file only contains the geometry (mesh coordinates) nfields is equal to ndim (2 or 3).
>> Stefan
>> 
>> 
>> On Aug 12, 2010, at 12:01 AM, <nek5000-users at lists.mcs.anl.gov> wrote:
>> 
>>> Stefan,
>>> 
>>> Thanks.  I figured that, but the binary file size doesn't seem to be adding up.    For example,  a field file that doesn't have geometry data is the size described by the initial thread, i.e.
>>> 
>>> 132 bytes + 4 bytes + nel* 4 bytes + nfields*nxyz*nel* wdsizo  +  nfields*2*nel * 4 bytes
>>> 
>>> My naive assumption was that a field file with xyz data would then have the additional space requirement of
>>> 
>>> nx*ny*nz*nel*wdsizo
>>> 
>>> but the file's bigger than that.  What info am I missing?  
>>> 
>>> --Mike
>>> 
>>> On Aug 11, 2010, at 3:50 PM, <nek5000-users at lists.mcs.anl.gov> wrote:
>>> 
>>>> Hi Mike,
>>>> 
>>>> vector fields (e.g. mesh coordinates) are stored in the following way:
>>>> 
>>>> LOOP over all elements
>>>> 	LOOP i = {x,y,z}
>>>> 		 i for all GLL points (internal element points)
>>>> 	ENDLOOP
>>>> ENDLOOP
>>>> 
>>>> 2D example with (E=2,N=2):
>>>> x1_1 x2_1 x3_1 y1_1 y2_1 y3_1 x1_1 x2_2 x3_2 y1_2 y2_2 y3_2
>>>> 
>>>> where x2_1 means the x-coordinate of the 2nd GLL point of element 1.
>>>> 
>>>> hth,
>>>> Stefan 
>>>> 
>>>> On Aug 11, 2010, at 11:34 PM, <nek5000-users at lists.mcs.anl.gov> wrote:
>>>> 
>>>>> 
>>>>> Hello All.  I found this helpful message from Stefan regarding the structure of a binary field file.   Could someone please tell me what the structure is when the geometry info is also contained?
>>>>> 
>>>>> Thanks!
>>>>> --Mike
>>>>> 
>>>>> nek5000-users at lists.mcs.anl.gov nek5000-users at lists.mcs.anl.gov 
>>>>>> Thu May 6 07:18:03 CDT 2010
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>>>>>> Hi Fred,
>>>>>> 
>>>>>> header: 132 bytes
>>>>>> endian test tag: 4 bytes
>>>>>> element mapping: nel* 4 bytes
>>>>>> data: nfields*nxyz*nel* wdsizo (where wdsizo is 4 or 8 bytes)
>>>>>> metadata (min/max values): nfields*2*nel * 4 bytes
>>>>>> 
>>>>>> Stefan
>>>>>> 
>>>>> 
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