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Whoops, I think the notation wasn't very good, sorry. This should
have been my previous message:<br>
<br>
Rank-0, is_0: [0 1 2] ... [633 634 635]<br>
Rank-0, is_1 [636 637 638] ... [729 730 731]<br>
Rank-1, is_0: [732 733 734] ... [1368 1369 1370]<br>
Rank-1, is_1 [1371 1372 1373] ... [1464 1465 1466]<br>
<br>
where I am printing the three first and last elements of each IS
object, so in fact the first processor has the range [0,635] (is0) +
[636,731] (is1) and the second one has [732, 1370] (is0) + [1371,
1466] (is1). This is actually the smallest (3D) problem I have
access to without changing anything, as I have hard-coded some
elements (i.e. boundary conditions). It still runs super quickly, so
it is not much of a problem to debug it as it is.<br>
<br>
Thanks you,<br>
NB<br>
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<div>I am now completely confused. The way PCFIELDSPLIT works,
when doing Schur complements, is to take</div>
<div>in two ISes, which can be thought of as lists of vector
rows. These two ISes must partition [0, N) if N is the</div>
<div>global size of the problem. So</div>
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<div> 1) The numbers you have above do not appear to be a
partition</div>
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</div>
<div> 2) The problem appears to be huge. Use a problem with
2-4 to debug.</div>
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<div> Thanks,</div>
<div><br>
</div>
<div> Matt</div>
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<div> Thanks!<br>
NB<br>
<br>
<br>
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-- <br>
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<div>What most experimenters take for granted before
they begin their experiments is infinitely more
interesting than any results to which their
experiments lead.<br>
-- Norbert Wiener</div>
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<div><a href="http://www.cse.buffalo.edu/~knepley/"
target="_blank" moz-do-not-send="true">https://www.cse.buffalo.edu/~knepley/</a><br>
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