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Matt,<br>
<br>
I'll have a go at writing Xdmf files.<br>
<br>
Am I right in thinking that VTK files are written sequentially?<br>
<br>
Thanks,<br>
<br>
David<br>
<br>
<div class="moz-cite-prefix">On 09/07/2020 20:17, Matthew Knepley
wrote:<br>
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<div dir="ltr">On Thu, Jul 9, 2020 at 2:51 PM David Scott <<a href="mailto:d.scott@epcc.ed.ac.uk" moz-do-not-send="true">d.scott@epcc.ed.ac.uk</a>>
wrote:<br>
</div>
<div class="gmail_quote">
<blockquote class="gmail_quote" style="margin:0px 0px 0px
0.8ex;border-left:1px solid
rgb(204,204,204);padding-left:1ex">Hello,<br>
<br>
I have written out a Vec using the (Fortran) HDF5 routines
provided by<br>
PETSc.<br>
I now want to import the data into ParaView 5.8.0 and
display a contour.<br>
I can read the data in using VisItPixieReader but the
contour tool is<br>
not available. Can I use the HDF5 files produced by PETSc
13.3.3 with<br>
ParaView and, if so, how?<br>
</blockquote>
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<div>When you call VecView(), it just writes an array of real
numbers to the HDF5 file. If Paraview can use an array</div>
<div>of real numbers, then you are all set. I don't know how
to make Paraview do that. What I do is to write an</div>
<div>Xdmf file that points to the HDF5 file for the data and
specifies the mesh using XML. Note that you can have</div>
<div>a DMDA or DMPlex write VTK files, which Paraview can read
directly.</div>
<div><br>
</div>
<div> Thanks,</div>
<div><br>
</div>
<div> Matt</div>
<div> </div>
<blockquote class="gmail_quote" style="margin:0px 0px 0px
0.8ex;border-left:1px solid
rgb(204,204,204);padding-left:1ex">
David<br>
<br>
<br>
<br>
The University of Edinburgh is a charitable body, registered
in Scotland, with registration number SC005336.<br>
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-- <br>
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<div>What most experimenters take for granted before
they begin their experiments is infinitely more
interesting than any results to which their
experiments lead.<br>
-- Norbert Wiener</div>
<div><br>
</div>
<div><a href="http://www.cse.buffalo.edu/~knepley/" target="_blank" moz-do-not-send="true">https://www.cse.buffalo.edu/~knepley/</a><br>
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