<html><head></head><body style="word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-space; ">I'm honestly not sure why I did that, however what I thought would be the obvious fix ( 'Mat h = *A' ) isn't, I'm still getting the error.<div><br></div><div>Is there a reason I can't do that?</div><div><br></div><div>-Andrew<br><div><br></div><div><br><div><div>On May 16, 2012, at 7:17 AM, Jed Brown wrote:</div><br class="Apple-interchange-newline"><blockquote type="cite"><div class="gmail_quote">On Wed, May 16, 2012 at 7:08 AM, Andrew Spott <span dir="ltr"><<a href="mailto:andrew.spott@gmail.com" target="_blank">andrew.spott@gmail.com</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div style="word-wrap:break-word">Not until you pointed it out… :). Though it probably should have been. It was late.<div><br></div><div>Though I'm not sure how to fix that… should I do a MatDestroy(A) at the beginning of that function every time?.</div>
<div><br></div><div>Is *A a pointer to the last used matrix, should I just do the mat duplicate into A?</div></div></blockquote><div><br></div><div>Do you really mean to only change A (the operator), but not B (the preconditioning matrix)?</div>
<div><br></div><div>Why do you want to create a new matrix instead of reusing those?</div></div>
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