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<p style="margin-top:0;margin-bottom:0">Dear Zhenrong,</p>
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<p style="margin-top:0;margin-bottom:0">I use one of the following to make the conversions:</p>
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<p style="margin-top:0;margin-bottom:0">Re_tau = .166 Re_b^0.88</p>
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<p style="margin-top:0;margin-bottom:0">Re_tau = 0.173 Re_b^0.875</p>
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<p style="margin-top:0;margin-bottom:0">per the attached. I apologize that I don't have the references for these formulas -- probably in Schlicting but I cannot recall at the moment.</p>
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<p style="margin-top:0;margin-bottom:0">Paul</p>
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<div id="divRplyFwdMsg" dir="ltr"><font face="Calibri, sans-serif" style="font-size:11pt" color="#000000"><b>From:</b> Nek5000-users <nek5000-users-bounces@lists.mcs.anl.gov> on behalf of nek5000-users@lists.mcs.anl.gov <nek5000-users@lists.mcs.anl.gov><br>
<b>Sent:</b> Friday, December 22, 2017 6:41:07 AM<br>
<b>To:</b> nek5000-users@lists.mcs.anl.gov<br>
<b>Subject:</b> [Nek5000-users] Reynolds number setting in the turbChannel example</font>
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Hello Neks</p>
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I am a new user of Nek5000 and my long term objective is to develop and implement some LES models in NEK5000. Now I am working with the turbChannel example.
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I want to make sure that the original parameter setting in the example is corresponding to Re_tau = 590 ? When the Reynolds number (p02) is set to 10935, my results show that the Re_tau is lower than 590.</p>
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The second question is that, if I want to simulate Re_tau = 180 case, what the Reynolds number (p02) should be? My understanding is that since the U_bar in the turbChannel is equal to 1, the the Reynolds number (p02) should be 2800, which is the Re base on
bulk mean velocity in J Kim, P Moin and R Moser 1986 JFM paper.</p>
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Any responds is greatly appreciated.</p>
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Regards</p>
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Zhenrong JING</p>
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PhD école centrale de Nantes</p>
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