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<p>Dear Hu,</p>
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<p>What information are you needing from another element.</p>
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<p>The usual approach, which appears relevant to your situation, is to recognize that communication is generally reciprocal: If element e needs data from element e', then e' also likely needs the same date from e.</p>
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<p>These operations are most readily handled through the gather-scatter operator, gs_op(), which can exchange data among participating processors. (All processors must participate, but some might not have data to exchange.)</p>
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<p>Are you trying to effect local averages? or, what?</p>
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<p>Many such operations can also be effected through existing spectral element operators, etc.</p>
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<p>hth,</p>
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<p>Paul</p>
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<div id="x_divRplyFwdMsg" dir="ltr"><font face="Calibri, sans-serif" color="#000000" style="font-size:11pt"><b>From:</b> Nek5000-users <nek5000-users-bounces@lists.mcs.anl.gov> on behalf of nek5000-users@lists.mcs.anl.gov <nek5000-users@lists.mcs.anl.gov><br>
<b>Sent:</b> Monday, July 24, 2017 9:06:50 PM<br>
<b>To:</b> nek5000-users@lists.mcs.anl.gov<br>
<b>Subject:</b> [Nek5000-users] How to get another element information that in the different processor?</font>
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<div class="PlainText">Hi all,<br>
I want to get another element information when I handle one element, and the two elements maybe not in the same processor. How to get another element information that in the different processor?<br>
<br>
Below is some of my code:<br>
1)for element e, get global element number;<br>
2)get the correspond element number at the inlet;<br>
3)call the ym1 value at the inlet element<br>
But I don't know how to get ym1(i,j,k,e_ele) in the e_nid processor.<br>
<br>
do e=1,nelv<br>
eg=lglel(e)<br>
call get_exyz(ex,ey,ez,eg,nelx,nely,nelz)<br>
e_in=(ez-1)*nelx*nely+(ey-1)*nelx+1<br>
e_nid=gllnid(e_in)<br>
e_ele=gllel(e_in)<br>
c if (nid.eq.e_nid) then <br>
do k=1,nz1<br>
do j=1,ny1<br>
do i=1,nx1<br>
temp=-ym1(i,j,k,e)*u_t/vis/A_plus<br>
cdyn(i,j,k,e)=cs0*(1-exp(temp))<br>
enddo<br>
enddo<br>
enddo<br>
c endif <br>
enddo<br>
<br>
Best wishes!<br>
Hu<br>
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